3^2^x-4(3^x^+^1)+27=0

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Solution for 3^2^x-4(3^x^+^1)+27=0 equation: 



3^2^x-4(3^x^+^1)+27=0

We multiply parentheses

3^2^x-12x+27-=0

We add all the numbers together, and all the variables

-12x+3^2^x=0

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